Re: [Full-disclosure] My private key

["Thor (Hammer of God)" <Thor@xxxxxxxxxxxxxxx>]

You're killin me over here ;)

And while funny, you actually do raise a good point - I should not use the term 
"totally secure" like that.  Rather, I should say that the encryption 
mechanisms used are based on industry standards and accepted mechanisms for 
strong encryption:  RSA2048 asymmetric, AES256 symmetric, and SHA256.  

I should have a full work up by the end of the weekend.

t

>-----Original Message-----
>From: musnt live [mailto:musntlive@xxxxxxxxx]
>Sent: Saturday, June 12, 2010 9:09 AM
>To: Thor (Hammer of God)
>Cc: Benji; Larry Seltzer; full-disclosure@xxxxxxxxxxxxxxxxx
>Subject: Re: [Full-disclosure] My private key
>
>On Sat, Jun 12, 2010 at 10:55 AM, Thor (Hammer of God)
><Thor@xxxxxxxxxxxxxxx> wrote:
>
>> It's totally portable, totally secure,
>
>Hello Full Disclosure, I'd like to warn you about "totally secure" and rubber
>hose cryptography. While Thor's bold statement of totally secure is so to say
>potential and possible the interrogators at Camp X-Ray beg to differ. Yes list
>"creative questioning" can yield Thor or anyone else's key and can be
>mathematically proving using a patended Craig S. Wright algorithm:
>
>Let P(n) be the statement that says that key+password+...+n = (n/2)(n+1)
>
>Firstly P(n) has to be checked for n=N, which is impossible
>
>It cannot be shown that the truth of P(k-1) implies the truth of P(k).
>Because, P(k-1) is the statement key+password+...+(k-1) = ((k-1)/2)k, which is
>assumed to be true for k greater than or equal to 2 however N cannot be
>calculated.
>
>Next add k to both sides of statement P(k-1) to get
>key+password+...+(k-1)+k = ((k-1)/2)k+k. Taking out a factor of k on
>the right hand side of the equation leaves key+password+...+k = (((k-
>1)/2)+1)k = k((k/2) + (1/2)) =(k/2)(k+1), which implies that P(k) is true.
>Condition 2 has been satisfied.
>
>Both conditions of the statement for the principle of mathematical induction
>have been satisfied but N is never established and the proof is inconclusive, 
>in
>other words P(n) is true for all positive integers n and nothing more given
>that: B(eer)||T(orture)||M(oney) trump all
>so:
>
>B+M=P(*) || T=P(*)
>
>Please contact Mr. Wright LLC, PhD, DDS, CISSP, GSE, GSE, GSE for future risk
>metrics. Did forget I mention GSE?

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