Re: [Full-Disclosure] gcc: Internal compiler error: program cc1 got fatal signal 11

[Raj Mathur <raju@linux-delhi.org>]

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>>>>> "Dale" == Dale Harris <rodmur@maybe.org> writes:

    Dale> On Sat, Jan 10, 2004 at 12:41:20AM +0100, m.esco@wp.pl
    Dale> elucidated:
    >> No Segmentation Fault on Slackware 9.1, Kernel 2.4.24, GCC
    >> 3.2.3.
    >> 
    >> 
    >> > Confimed - Segmentation Fault
    >> > 
    >> > OS = Slackware 9.1.0 > Kernel = 2.4.22 > GCC = 3.2.3
    >> > 
    >> > int main(void) > { > printf("%c","msux"[0xcafebabe]); > } > $
    >> gcc gcc-crash.c > $ ./a.out > Segmentation fault

    Dale> Well, honestly... is this interesting if seg. faults when
    Dale> you execute it?  Or am I just missing something?  You're
    Dale> accessing an array that hasn't been defined, that is a big
    Dale> "DUH!" in my book.  It is interesting if it kills the
    Dale> compiler while trying to compile it, when it should be
    Dale> issuing a syntax error, not if the binary is executed.
    Dale> Hell, I have programs seg.  fault all the time, no surprise
    Dale> there.

The program is not accessing an array that hasn't been defined.

If you go back to K&R you'd remember that a[i] is treated as *(a+i).
Hence, addition being commutative, it doesn't matter whether you use
a[i] or i[a], as long as one of (a, i) is an integer type and the
other a pointer to a non-void, known type.

To illustrate, try the following:

main()
{
        char array[] = "ABCD";
        printf ( "%c\n" , array[2] );
        printf ( "%c\n" , 2[array] );
}

Both printfs will print out "C".

Regards,

- -- Raju
- -- 
Raj Mathur                raju@kandalaya.org      http://kandalaya.org/
       GPG: 78D4 FC67 367F 40E2 0DD5  0FEF C968 D0EF CC68 D17F
                      It is the mind that moves
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